Question 318933
Put the line in slope intercept form, {{{y=mx+b}}
{{{(k+1)x+2y=6}}}
{{{2y=-(k+1)x+6}}}
{{{y=-((k+1)/2)x+6}}}
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The slope {{{m}}} is,
{{{m=-((k+1)/2)}}}
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I think you want to solve for {{{m=-1}}} and {{{m=3}}}.
{{{-1=-((k+1)/2)}}}
{{{k+1=2}}}
{{{highlight(k=1)}}}
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{{{3=-((k+1)/2)}}}
{{{k+1=-6}}}
{{{highlight(k=-7)}}}