Question 318965
{{{x^2+8x=10x+3}}}
{{{x^2-2x-3=0}}}
{{{(x-3)(x+1)=0}}}
Two solutions:
{{{x-3=0}}}
{{{highlight(x=3)}}}
.
.
.
{{{x+1=0}}}
{{{highlight(x=-1)}}}