Question 318963
1) 36y^5-39y^4-12y^3
common factor: 3y^3
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= (3y^3)(12y^2 - 13y - 4)
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= (3y^3)(12y^2 - 16y + 3y -4)
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= (3y^3)(4y(3y-4)+(3y-4))
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= (3y^3)(3y-4)(4y+1)
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2) Factor completely 
4x^3-10x^2-24x
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= 2x(2x^2 - 5x - 12) 
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= 2x(2x^2-8x+3x-12)
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= 2x(2x(x-4)+3(x-4))
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= 2x(x-4)(2x+3)
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Cheers,
Stan H.
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