Question 318857
{{{x^2=15x-36 }}}
{{{x^2-15x+36=0}}}
You can factor this quadratic equation,
{{{(x-12)(x-3)=0}}}
Two solutions:
{{{x-12=0}}}
{{{highlight( x=12)}}}
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{{{x-3=0}}}
{{{highlight(x=3)}}}
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