Question 318686
First factor: {{{2x}}}
{{{2x(x+2)=2x^2+4x}}}
Subtract from the original polynomial to get the remainder,
{{{(2x^2+x+5)-(2x^2+4x)=-3x+5}}}
Second factor: {{{-3}}}
{{{-3(x+2)=-3x-6}}}
Subtract from the previous remainder to get the new remainder,
{{{(-3x+5)-(-3x-6)=11}}}
No further division is possible.
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Gather up the factors and the remainder.
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{{{(2x^2+x+5)/(x+2)=2x-3+(11/(x+2))}}}