Question 318691
Let x = the first integer
Let x + 2 = the second integer (because 3 is 2 more than 1, and 5 is 2 more than 3, and so on...)


Let x + 4 = the 3rd integer


The two larger numbers (x+2) and x+4) multiply to 195.

195 = (x+2)(x+4)
195 = x^2 + 6x + 8


You have to factor this to solve it:

0 = x^2 +6x +8 -195
0 = x^2+6x-187


To factor this, you have to find 2 numbers that multiply to -195 and have a difference of 6. Or you could use the Quadratic Equation, with a=1 b=6 and c=-187


Either way you will find that those numbers are -17 and 11. 

The three numbers are either 11, 13, and 15 or -17, -15, and -13.