Question 318585
a) Find the slope.
{{{m=(y2-y1)/(x2-x1)=(4-(-2))/(4-2)=6/2}}}
{{{m=3}}}
Use the slope-intercept form of a line, {{{y=mx+b}}}
Use either point to solve for b.
{{{y=3x+b}}}
{{{4=3(4)+b}}}
{{{b=4-12}}}
{{{b=-8}}}
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{{{highlight(y=3x-8)}}}
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{{{drawing(300,300,-8,8,-8,8,circle(2,-2,.3),circle(4,4,0.3),grid(1),graph(300,300,-8,8,-8,8,3x-8))}}}
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b) Perpendicular line have slopes that are negative reciprocals.
{{{m1*m2=-1}}}
{{{m1=1}}}
{{{m2=-1}}}
{{{y=-x+b}}}
Use the point to solve for b.
{{{y=-x+b}}}
{{{-8=-(0)+b}}}
{{{b=-8}}}
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{{{highlight(y=-x-8)}}}
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{{{drawing(300,300, -12,4,-12,4, circle(0,-8,.3),grid(1),graph(300,300,-12,4,-12,4, x+5,-x-8))}}}
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