Question 318455
Do I pick which one to solve? 
I guess I don't understand the "or"
{{{2x-3y>9}}}
{{{-3y>-2x+9}}}
{{{y>(2/3)x-3}}}
Plot the line {{{y=(2/3)x-3}}}
{{{graph(300,300,-4,8,-8,4,(2/3)x-3)}}}
Now pick a point on either side of the line.
Choose (0,0) because that's easiest.
If it solves the inequality, it's in the solution region.
If it doesn't then it's not.
(0,0),
{{{y>(2/3)x-3}}}
{{{0>(2/3)(0)-3}}}
{{{0>-3}}}
False, so (0,0) is not in the solution region.
Shade the other region.
*[invoke plot_any_inequality "y < (2/3)x-3", -4, 8, -8, 4, 300, 300]