Question 318367
I have a feeling that the equation should be {{{4^(16)=2^(x+7)}}}



{{{4^(16)=2^(x+7)}}} Start with the given equation.



{{{(2^2)^(16)=2^(x+7)}}} Rewrite 4 as {{{2^2}}}



{{{2^(2*16)=2^(x+7)}}} Multiply the exponents.



{{{2^32=2^(x+7)}}} Multiply 2 and 16 to get 32



Since the bases are equal, this means that the exponents are equal. This means that 


{{{32=x+7}}}



{{{32-7=x}}} Subtract 7 from both sides.



{{{25=x}}} Combine like terms.



So the solution is {{{x=25}}}