Question 318395
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ -\ y\ =\ 12]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ xy\ =\ 325]


Substitute:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (y\ +\ 12)y\ =\ y^2\ +\ 12y\ =\ 325]


Solve the quadratic:  Hint, it factors neatly.  Except that the problem specified whole numbers, which are all positive, there would be two answers to this problem.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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