Question 318371
{{{(8+3i)*(7+4i)}}} Start with the given expression.



{{{(8)(7)+(8)(4i)+(3i)(7)+(3i)(4i)}}} FOIL.



{{{56+32i+21i+12i^2}}} Multiply.



{{{56+32i+21i+12(-1)}}} Replace {{{i^2}}} with {{{-1}}}. Note: {{{i^2=-1}}}.



{{{56+32i+21i-12}}} Multiply.



{{{44+53i}}} Combine like terms.



So {{{(8+3i)*(7+4i)=44+53i}}}.



So the expression is now in standard form {{{a+bi}}} where {{{a=44}}} and {{{b=53}}}