Question 318317
Find the inverse of:
{{{y = 7x^2 - 3}}} Interchange the x and y.
{{{x = 7y^2 - 3}}} Solve for y. Add 3 to both sides.
{{{x+3 = 7y^2}}} Divide both sides by 7.
{{{(x+3)/7 = y^2}}} Take the square root of both sides.
{{{sqrt((x+3)/7) = y}}} or {{{y = sqrt((x+3)/7)}}}
The inverse of a function of x (f(x)) is often written as: {{{f^(-1)(x)}}} so the answer can be written as:
{{{f^(-1)(x) = sqrt((x+3)/7)}}}