Question 318328
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ 2\ =\ \sqrt{y\ +\ 4}]


Square both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y^2\ -\ 4y\ +\ 4\ =\ y\ +\ 4]


Collect like terms on the left:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y^2\ -\ 5y\ =\ 0]


Now just solve the quadratic.  You will get two roots, but one or both may be extraneous.  Check both.  Note *[tex \LARGE \sqrt{y\ +\ 4}] is the POSITIVE square root.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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