Question 318266
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The graph of the equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{(x\,-\,h)^2}{a^2}\ +\ \frac{(y\,-\,k)^2}{b^2}\ =\ 1]


Is an ellipse centered at *[tex \LARGE (h,k)].  Presuming *[tex \LARGE a\ >\ b], then *[tex \LARGE a] is the measure of the semi-major axis and *[tex \LARGE b] is the measure of the semi-minor axis.


Your center is at *[tex \LARGE (0, 1)], major axis 14, and minor axis 8


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x^2}{49}\ +\ \frac{(y\,-\,1)^2}{16}\ =\ 1]






John
*[tex \LARGE e^{i\pi} + 1 = 0]
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