Question 318126
{{{x^2*k-y^2*k}}} Start with the given expression.



{{{k(x^2-y^2)}}} Factor out the GCF 'k'



{{{k(x+y)(x-y)}}} Factor {{{x^2-y^2}}} to get {{{(x+y)(x-y)}}} using the difference of squares formula.



So {{{x^2*k-y^2*k=k(x+y)(x-y)}}}