Question 317970
(Solve by completing the square.)
1.x^2-6x=1
x^2-6x+9 = 1+9
(x-3)^2 = 10
x-3 = sqrt(10) or x-3 = -sqrt(10)
x = 3+sqrt(10) or x = 3-sqrt(10)

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2. 2x^2-3x+1= 0
2x^2 - 3x = -1
2(x^2-(3/2)x) = -1
2(x^2-(3/2)x+(3/4)^2) = -1 + 2(3/4)^2
2(x-(3/2))^2 = 1/8
(x-(3/2))^2 = 1/16
x-(3/2) = +-1/4
x = (3/2)+(1/4) or x = (3/2)-(1/4)
x = (7/4) or x = 5/4
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3.x^2-x-1=0 
I'll leave this one to you.
Cheers,
Stan H.
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