Question 317830
What if you used logs to the base 10?
{{{2^x = 5}}}
{{{log(2^x) = log(5)}}}
{{{x*log(2) = log(5)}}}
{{{x = log(5)/log(2)}}}
{{{x = .699/.301}}}
{{{x = 2.322}}}
I got the same answer using natural logs
Did you goof with the calculator?