Question 317816


First let's find the slope of the line through the points *[Tex \LARGE \left(6,3\right)] and *[Tex \LARGE \left(6,1\right)]



Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(6,3\right)]. So this means that {{{x[1]=6}}} and {{{y[1]=3}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(6,1\right)].  So this means that {{{x[2]=6}}} and {{{y[2]=1}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(1-3)/(6-6)}}} Plug in {{{y[2]=1}}}, {{{y[1]=3}}}, {{{x[2]=6}}}, and {{{x[1]=6}}}



{{{m=(-2)/(6-6)}}} Subtract {{{3}}} from {{{1}}} to get {{{-2}}}



{{{m=(-2)/(0)}}} Subtract {{{6}}} from {{{6}}} to get {{{0}}}



Remember, you <b>cannot</b> divide by zero. So this means that the slope is undefined.



Since the slope is undefined, this means that the equation of the line through the points *[Tex \LARGE \left(6,3\right)] and *[Tex \LARGE \left(6,1\right)] is {{{x=6}}}.