Question 317667
part of a fuel moisture formula I am trying to solve.. the formula is: 
MC=351/e^(DC/390) 
I have made a physical observation determing the value of MC but now I need to solve for DC.
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MC=351/e^(DC/390)
e^(DC/390) = 351/MC
DC/390 = ln(351/MC)
DC = 390*ln(351/MC)