Question 317652
{{{f(1)=362/(1^2+1)=362/2=181}}}
{{{f(19)=362/(19^2+1)=362/362=1}}}
Linear functions have the form, {{{y=mx+b}}}
Calculate the slope, {{{m}}},using the two points, ({{{1}}},{{{181}}}) and ({{{19}}},{{{1}}})
{{{m=(y2-y1)/(x2-x1)=(1-181)/(19-1)=-180/18=-10}}}
Then use either point to find {{{b}}}.
{{{y=-10x+b}}}
{{{1=-10(19)+b}}}
{{{1=-190+b}}}
{{{b=191}}}
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{{{highlight(y=-10x+191)}}}
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{{{drawing(300,300,-2,20,-10,200,grid(1),circle(1,181,.5),circle(19,1,.5),graph(300,300,-2,20,-10,200,-10x+191,362/(x^2+1)))}}}