Question 317655
{{{a^2+b^2=16+9=25}}}
{{{a^2-b^2=16-9=7}}}
{{{(a+b)^2=(4+3)^2=49}}}
{{{2a^2-3ab+b^2=2(16)-3(12)+9=32-36+9=5}}}
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{{{ ((a^2+b^2)(a^2-b^2))/((a+b)^2(2a^2-3ab+b^2))=(25(7))/(49(5))=highlight(175/245)=35/49 }}}
I get a different denominator.