Question 317479
Find the variance of the binomial distribution with the given values.

 
n = 50
p = 0.9 


Since p, or probability of success is 0.9, then q, or probability of failure = .1 (1.0 - 0.9)


Now we have: 
n = 50
p = 0.9 
q = 0.1


Standard Deviation (SD) = {{{sqrt(npq)}}}


Variance = {{{SD^2}}}, or {{{(sqrt(npq))^2}}} = npq, or n*p*q = 50(.9)(.1) = {{{highlight_green(4.5)}}}