Question 317498
The volume V of a right circular cone varies jointly as the square of the radius R and the height H. 
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V = k(R^2*H)
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Determine what happens to V when R is six times as large.
Let r = 6R 
V = k(r^2*H)
V = k((6R)^2*H)
V = k(36R^2*H)
V = 36k(R^2*H)
 
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Ans: The volume is multiplied by 36
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Cheers,
Stan H.
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