Question 317387
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Not completely sure why you thought you needed a lowest common denominator.


Just multiply across the binomials using the distributive property. The fractions will take care of themselves:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -9\left(2x\ -\ \frac{1}{3}\right)\ =\ 4\left(-\frac{1}{2}x\ +\ \frac{1}{4}\right)]



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -18x\ +\ 3\ =\ -2x\ + 1]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -18x\ +\ 2x\ =\ -3\ +\ 1]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -16x\ =\ -2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{1}{8}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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