Question 36969
find the range of y= sq rt 9-x^3
HOPE YOU MEAN SQRT(9-X^3) AND NOT SQRT(9) - X^3..ASSUMING SO
DOMAIN IS 9-X^3>=0..SINCE SQRT. OF NEGATIVE NUMBER IS IMAGINARY
9>=X^3
FOR THESE VALUES OF X Y CAN TAKE 0 TO PLUS INFINITY AS IN GENERAL WE TKE POSTIVE VALUE OF SQRT.HOWEVER SQRT CAN BE -VE ALSO AND HENCE Y CAN HAVE VALUES FROM 0 TO -INFINITY TOO