Question 317352
you are on a roof of a building. you throw a ball into the air with a velocity of 32ft/s. the ball is 48 ft above the ground when it leaves your hand. how many seconds will it take for the ball to reach the ground? use the vertical motion formula -16t^+ vt + s =h.
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h(t) = -16t^2 + vt + s
v = initial velocity = 32 ft/sec
s = initial height = 48 feet
h(t) = -16t^2 + 32t + 48
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Find when h(t) = 0
-16t^2 + 32t + 48 = 0
-t^2 + 2t + 3 = 0
(-t - 1)*(t - 3) = 0
t = -1 second (Ignore)
t = 3 seconds