Question 317222

{{{sqrt(9x+67)=x+5}}}
{{{9x+67=(x+5)^2}}}
{{{9x+67=x^2+10x+25}}}
{{{x^2+x-42=0}}}
{{{(x+7)(x-6)=0}}}
Two solutions:
{{{x+7=0}}}
{{{highlight(x=-7)}}}
.
.
.
{{{x-6=0}}}
{{{highlight(x=6)}}}