Question 317206
solve algerbraically over the interval (0,2pi)
2sin^2(x)+3=4 
.
2sin^2(x)=1
sin^2(x)=1/2
take the square root of both sides: 
sin(x) = {{{sqrt(1/2)}}}
Normalizing:
sin(x) = {{{sqrt(2)/2}}}
.
Now, using the "unit circle" discover what angle satisfies the above and it would be:
(pi)/4 and 3(pi)/4