Question 317198
{{{N(N+2)=168}}}
{{{N^2+2N=168}}}
Complete the square. 
{{{N^2+2N+1=168+1}}}
{{{(N+1)^2=169}}}
{{{N+1=0 +- 13}}}
{{{N=-1 +- 13}}}
Two solutions:
{{{N=-14}}}
The integers would be -14 and -12.
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{{{N=12}}}
The integers would be 12 and 14.