Question 317147
{{{(3/(x^2+11x-26))-(2/(x^2+16x+39))=3/((x+13)(x-2))-2/((x+13)(x+3))}}}
Find a common denominator.
{{{(3/(x^2+11x-26))-(2/(x^2+16x+39))=(3(x+3))/((x+13)(x+3)(x-2))-(2(x-2))/((x+13)(x+3)(x-2))}}}
{{{(3/(x^2+11x-26))-(2/(x^2+16x+39))=(3x+9-2x+4)/((x+13)(x+3)(x-2))}}}
{{{(3/(x^2+11x-26))-(2/(x^2+16x+39))=((x+13))/((x+13)(x+3)(x-2))}}}
{{{(3/(x^2+11x-26))-(2/(x^2+16x+39))=1/((x+3)(x-2))}}}