Question 317088
{{{(x^(-2/3)*y^(k-1)*z^3)/(x*y^k*z^(-2/3))=x^(-2/3-1)*y^(k-1-k)*z^(3-2/3)}}}
{{{(x^(-2/3)*y^(k-1)*z^3)/(x*y^k*z^(-2/3))=x^(-5/3)*y^(-1)*z^(7/3)}}}
{{{(x^(-2/3)*y^(k-1)*z^3)/(x*y^k*z^(-2/3))=z^(7/3)/(x^(5/3)*y) }}}