Question 317125
{{{1/(x+3)+6/x^2=1}}}
{{{x^2+6*(x+3)=x^2(x+3)}}}
{{{x^2+6x+18=x^3+3x^2}}}
{{{x^3+2x^2-6x-18 =0 }}}
.
.
.
{{{ drawing( 300, 300, -10, 10, -10,10,grid(1),circle(2.6976,0,.3),graph( 300, 300, -10, 10, -10, 10, x^3+2x^2-6x-18) )}}} 
As you can see there is one real root and two complex roots for this equation (since it only crosses the x-axis at one point).
I used the cubic equation solver at www.1728.com/cubic.htm to find the real root.
.
.
.
{{{highlight(x=2.6976)}}}