Question 317003
Factor:
{{{16x^3-t^4x^3}}} First factor the {{{x^3}}}
{{{x^3(16-t^4)}}} The binomial can be seen as the difference of squares.
{{{x^3((4)^2-(t^2)^2)}}} Factor the difference of squares.
{{{x^3(4-t^2)(4+t^2)}}} Now you have another difference of squares {{{(2^2-t^2)}}} so you can factor this as well.
{{{highlight(x^3(2+t)(2-t)(4+t^2))}}}...and there you have it!