Question 316995
{{{-uz+2t+tu-2z}}} Start with the given expression



{{{-uz+tu-2z+2t}}} Rearrange the terms.



{{{(-uz+tu)+(-2z+2t)}}} Group the terms



{{{u(-z+t)+2(-z+t)}}} Factor out the GCF {{{u}}} out of the first group. Factor out the GCF {{{2}}} out of the second group



{{{(u+2)(-z+t)}}} Since we have the common term {{{-z+t}}}, we can combine like terms



{{{(u+2)(t-z)}}} Rearrange the terms.



So {{{-uz+2t+tu-2z}}} factors to {{{(u+2)(t-z)}}}



In other words, {{{-uz+2t+tu-2z=(u+2)(t-z)}}}