Question 316990
{{{9z^2+zu+27z+3u}}} Start with the given expression



{{{(9z^2+zu)+(27z+3u)}}} Group the terms



{{{z(9z+u)+3(9z+u)}}} Factor out the GCF {{{z}}} out of the first group. Factor out the GCF {{{3}}} out of the second group



{{{(z+3)(9z+u)}}} Since we have the common term {{{9z+u}}}, we can combine like terms



So {{{9z^2+zu+27z+3u}}} factors to {{{(z+3)(9z+u)}}}



In other words, {{{9z^2+zu+27z+3u=(z+3)(9z+u)}}}