Question 316978


{{{64-9u^2}}} Start with the given expression.



{{{(8)^2-9u^2}}} Rewrite {{{64}}} as {{{(8)^2}}}.



{{{(8)^2-(3u)^2}}} Rewrite {{{9u^2}}} as {{{(3u)^2}}}.



Notice how we have a difference of squares {{{A^2-B^2}}} where in this case {{{A=8}}} and {{{B=3u}}}.



So let's use the difference of squares formula {{{A^2-B^2=(A+B)(A-B)}}} to factor the expression:



{{{A^2-B^2=(A+B)(A-B)}}} Start with the difference of squares formula.



{{{(8)^2-(3u)^2=(8+3u)(8-3u)}}} Plug in {{{A=8}}} and {{{B=3u}}}.



So this shows us that {{{64-9u^2}}} factors to {{{(8+3u)(8-3u)}}}.



In other words {{{64-9u^2=(8+3u)(8-3u)}}}.