Question 316961
x,x+2,x+4
x and x+2 are the 2 smaller numbers
{{{2(x(x+2))=88+((x+2)(x+4))}}} "twice the product of the two smaller integers is 88 more than the product of the two larger integers"
{{{(2x^2+4x)=88+(x^2+6x+8)}}} add
{{{2x^2+4x=x^2+6x+96}}} subtract
{{{x^2-2x-96=0}}}
doesnt come out to a whole number so either thats suppose to be that way in the answer or the question was written wrong.
x= 10.8488578017961 or -8.8488578017961
(x+2)= 12.8488578017961 or -6.8488578017961
(x+4)= 14.8488578017961 or -4.8488578017961
*[invoke quadratic "x", 1, -2, -96]