Question 316856
{{{f(x) = x^2 + 8x + 13}}}
.
Since the coefficient associated with the {{{x^2}}} term is POSITIVE (think "happy face"), we KNOW that it is a parabola that opens upwards -- therefore there will be a MINIMUM.
.
The minimum then corresponds to the "vertex".
Axis of symmetry:
x = -b/(2a) = -8/2 = -4
.
{{{f(-4) = (-4)^2 + 8(-4) + 13}}}
{{{f(-4) = 16 - 32 + 13}}}
{{{f(-4) = -3}}}