Question 36897
165=24X+32X+4X~2 24X IS 2*12*x WHERE X IS THE FRAME WIDTH & 32X IS 2*16*X 
THE 4 COENERS HAVE AREA OF X~2 THUS THE 4X~2 

165=56X+4X~2 or 4x~2+56x-165=0 OR (2X+33)(2X-5)=0 OR x=5/2 OR 2.5 INCH WIDE 

FRAME