Question 316775


From {{{s^2+3s+6}}} we can see that {{{a=1}}}, {{{b=3}}}, and {{{c=6}}}



{{{D=b^2-4ac}}} Start with the discriminant formula.



{{{D=(3)^2-4(1)(6)}}} Plug in {{{a=1}}}, {{{b=3}}}, and {{{c=6}}}



{{{D=9-4(1)(6)}}} Square {{{3}}} to get {{{9}}}



{{{D=9-24}}} Multiply {{{4(1)(6)}}} to get {{{(4)(6)=24}}}



{{{D=-15}}} Subtract {{{24}}} from {{{9}}} to get {{{-15}}}



Since the discriminant is less than zero, this means that there are two complex solutions.



In other words, there are no real solutions.