Question 316707
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Let *[tex \Large x] represent the width.  Then *[tex \Large 5x] must represent the  length. The area is the length times the width.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5x^2\ =\ 125]


Solve for *[tex \Large x] to get the width.  Multiply by 5 to get the length.


Then calculate the perimeter using:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P\ =\ 2l\ +\ 2w\ =\ 2(5x)\ +\ 2x]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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