<PRE><B>Question 316685</B>
in a shipment of 15 sets of golf clubs, 3 are left handed. 
if 4 sets of golf clubs are selected, 
---
Binomial Problem with n = 4 ; p = 1/5
----------
what is the proability that 
exactly 1 is left handed = 4C1(1/5)(4/5)^3 = 0.4096
---------- 
at least 1 is left-handed = 1 - P(x=0) = 1-(4/5)^4 = 0.5904
---------- 
no more than 2 are left handed = binomcdf(4,1/5,2) = 0.9728
---------------------- 
what is the mean number of left handed sets of golf clubs that you would expect to find in the sample of 4 sets of golf clubs:::np = 4*(1/5) = 4/5
---------------------------------
Cheers,
Stan H.
================================
</PRE>