Question 316670
Use a substitution.
Let {{{u=4x-1}}}
{{{ (4x-1)^2-6(4x-1)+25=0 }}}
{{{u^2-6u+25=0}}}
{{{(u^2-6u+9)+16=0}}}
{{{(u-3)^2=-16}}}
{{{u-3=0 +- 4i}}} 
{{{u=3 +- 4i}}}
{{{4x-1=3 +- 4i}}}
{{{4x=4 +- i}}}
{{{highlight_green(x=1 +- i)}}} where {{{i=sqrt(-1)}}}