Question 315640
First we must find the slope of the line x-5y=4. We shall put it into slope-intercept form. 

{{{x-5y=4}}}
{{{x = 4 + 5y }}} 
{{{5y = x - 4 }}} 
{{{y = (x/5) - (4/5) }}} 

The slope of this line is {{{m=1/5}}}. The slope of a line perpendicular to this is -5. 

The line must pass through the point (-1,1). 

We can give the equation of the line now in point-slope form: {{{y - y_0 = m(x-x_0) }}}, where {{{m=-5}}}, {{{x_0 = -1}}}, and {{{y_0 = 1}}}. 

So our equation is {{{y - 1 = -5 (x - (-1) ) }}}. 

We can convert this to slope-intercept form too: 

{{{y - 1 = -5 (x + 1) }}} 

{{{y - 1 = -5x - 5 }}} 

So the line in slope-intercept form is: {{{ y = -5x - 4 }}} 

Also, we can convert this to standard form as: {{{ 5x + y = -4 }}}. 

I hope this helps!