Question 316427
Use the Pythagorean theorem,
{{{A^2+B^2=H^2}}}
{{{S^2+(S+23)^2=(S+23+2)^2}}}
{{{S^2+(S^2+46S+529)=(S^2+50S+625)}}}
{{{2S^2+46S+529=S^2+50S+625}}}
{{{S^2-4S-96=0}}}
{{{(S-12)(S+8)=0}}}
Only the positive solution makes sense in this case,
{{{S-12=0}}}
Short:{{{S=12}}}
Long:{{{L=S+23=35}}}
Hypotenuse:{{{H=L+2=37}}}