Question 36831
the difference of the squares of two consecutive integers is 21. find the integers.


Let the 2 integers be x and x+1

(x+1)^2 -  x^2 = 21
x^2 +2x +1 - x^2 = 21
2x + 1 = 21
2x = 20
x = 10


Therefore x+1 = 11
The 2 integers are 10,11