Question 316309
Let's look at the denominator {{{ (-y-2) }}}. Since both terms are negative, we can factor out a -1 and rewrite this as {{{ (-y-2) = -1 * (y+2) }}}. You can check this using the distributive property. 

Now our fraction looks like this: 
{{{ (y+2) / (-y -2) = (y+2) / (-1 * (y+2)) }}}. 

We can cancel the (y+2) factor in the numerator and denominator and we are left with 

{{{(y+2) / (-1 * (y+2)) = 1/(-1) = -1 }}}, so we get <b>C</b>. 



By the way, the solution given by nycfunction is incorrect 
First, the factoring is done wrong, as -1(y+2) = -y -2 is the correct way to do it following the distributive property. -1(y-2) = -y + 2, (not the +2 which resulted from -1 times -2), which is not what the question was asking for. 
Second, the cancellation is wrong. If you have {{{ (x+3)/(x+1) }}}, you can't just cancel the x and say this equals {{{ 3 / 1 }}} which is 3. To see why this is wrong, consider the case when x = 1. Then we should get {{{ (1 + 3) / (1 + 1)  = 4 / 2 = 2 }}}, NOT 3. Clearly, you can't cancel a part of a factor.