Question 316169
You can break the hexagon into 6 equilateral triangles. 
You can then find the height using the side {{{s/2}}}, hypotenuse {{{s}}}, and the Pythagorean theorm to get {{{h=sqrt(3)/2}}}.
{{{(s/2)^2+h^2=s^2}}}
{{{h^2=s^2-s^2/4}}}
{{{h^2=(3/4)s^2}}}
{{{h=(sqrt(3)/2)s}}}
Then the area of 6 triangles would be
{{{A= 6*(1/2)bh}}}
{{{A =3hb}}}
{{{A=3(sqrt(3)/2)s*s}}}
{{{A =((3sqrt(3))/2)s^2}}}