Question 316164

{{{(7N^(-2)Y^(-4))/(22N^6Y^7)=(7/22)N^(-2-6)Y^(-4-7)}}}
{{{(7N^(-2)Y^(-4))/(22N^6Y^7)=(7/22)N^(-8)Y^(-11)}}}
{{{(7N^(-2)Y^(-4))/(22N^6Y^7)=7/(22N^(8)Y^(11))}}}