Question 316293
{{{(6z^2+36z+54)/(z^2-3z-18)}}} Start with the given expression.



{{{(6(z+3)(z+3))/(z^2-3z-18)}}} Factor the numerator.



{{{(6(z+3)(z+3))/((z-6)(z+3))}}} Factor the denominator.



{{{(6(z+3)*highlight((z+3)))/((z-6)*highlight((z+3)))}}} Highlight the common terms.



{{{(6(z+3)*cross((z+3)))/((z-6)*cross((z+3)))}}} Cancel out the common terms.



{{{(6(z+3))/(z-6)}}} Simplify.



{{{(6z+18)/(z-6)}}} Distribute.



So {{{(6z^2+36z+54)/(z^2-3z-18)}}} simplifies to {{{(6z+18)/(z-6)}}}



In other words, {{{(6z^2+36z+54)/(z^2-3z-18)=(6z+18)/(z-6)}}}